How to filter a dictionary according to an arbitrary condition function?

Question

You can use a dict comprehension:

{k: v for k, v in points.items() if v[0] < 5 and v[1] < 5}

And in Python 2, starting from 2.7:

{k: v for k, v in points.iteritems() if v[0] < 5 and v[1] < 5}

dict((k, v) for k, v in points.items() if all(x < 5 for x in v))

You could choose to call .iteritems() instead of .items() if you're in Python 2 and points may have a lot of entries.

all(x < 5 for x in v) may be overkill if you know for sure each point will always be 2D only (in that case you might express the same constraint with an and) but it will work fine;-).

points_small = dict(filter(lambda (a,(b,c)): b<5 and c < 5, points.items()))

>>> points = {'a': (3, 4), 'c': (5, 5), 'b': (1, 2), 'd': (3, 3)}
>>> dict(filter(lambda x: (x[1][0], x[1][1]) < (5, 5), points.items()))

{'a': (3, 4), 'b': (1, 2), 'd': (3, 3)}

dict((k, v) for (k, v) in points.iteritems() if v[0] < 5 and v[1] < 5)

I think that Alex Martelli's answer is definitely the most elegant way to do this, but just wanted to add a way to satisfy your want for a super awesome dictionary.filter(f) method in a Pythonic sort of way:

class FilterDict(dict):
    def __init__(self, input_dict):
        for key, value in input_dict.iteritems():
            self[key] = value
    def filter(self, criteria):
        for key, value in self.items():
            if (criteria(value)):
                self.pop(key)

my_dict = FilterDict( {'a':(3,4), 'b':(1,2), 'c':(5,5), 'd':(3,3)} )
my_dict.filter(lambda x: x[0] < 5 and x[1] < 5)

Basically we create a class that inherits from dict, but adds the filter method. We do need to use .items() for the the filtering, since using .iteritems() while destructively iterating will raise exception.

dict((k, v) for (k, v) in points.iteritems() if v[0] < 5 and v[1] < 5)