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How do I check the difference, in seconds, between two dates?

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How do you find the difference in seconds between two dates?

We have the startDate and endDate which we can convert both to timestamps in milliseconds with getTime . Then we subtract the timestamp of endDate by the timestamp of startDate . This will return the timestamp difference in milliseconds. So we divide the difference by 1000 to get the difference in seconds.

How do you find seconds on a date?

var timestampInMilliseconds = +new Date; var timestampInSeconds = +new Date / 1000; // A float value; not an intger. timestampInSeconds = Math. floor(+new Date / 1000); // Floor it to get the seconds.

How do I calculate the time difference between two timestamps?

If you'd like to calculate the difference between the timestamps in seconds, multiply the decimal difference in days by the number of seconds in a day, which equals 24 * 60 * 60 = 86400 , or the product of the number of hours in a day, the number of minutes in an hour, and the number of seconds in a minute.


if you want to compute differences between two known dates, use total_seconds like this:

import datetime as dt

a = dt.datetime(2013,12,30,23,59,59)
b = dt.datetime(2013,12,31,23,59,59)

(b-a).total_seconds()

86400.0

#note that seconds doesn't give you what you want:
(b-a).seconds

0


import time  
current = time.time()

...job...
end = time.time()
diff = end - current

would that work for you?


>>> from datetime import datetime

>>>  a = datetime.now()

# wait a bit 
>>> b = datetime.now()

>>> d = b - a # yields a timedelta object
>>> d.seconds
7

(7 will be whatever amount of time you waited a bit above)

I find datetime.datetime to be fairly useful, so if there's a complicated or awkward scenario that you've encountered, please let us know.

EDIT: Thanks to @WoLpH for pointing out that one is not always necessarily looking to refresh so frequently that the datetimes will be close together. By accounting for the days in the delta, you can handle longer timestamp discrepancies:

>>> a = datetime(2010, 12, 5)
>>> b = datetime(2010, 12, 7)
>>> d = b - a
>>> d.seconds
0
>>> d.days
2
>>> d.seconds + d.days * 86400
172800

We have function total_seconds() with Python 2.7 Please see below code for python 2.6

import datetime
import time  

def diffdates(d1, d2):
    #Date format: %Y-%m-%d %H:%M:%S
    return (time.mktime(time.strptime(d2,"%Y-%m-%d %H:%M:%S")) -
               time.mktime(time.strptime(d1, "%Y-%m-%d %H:%M:%S")))

d1 = datetime.now()
d2 = datetime.now() + timedelta(days=1)
diff = diffdates(d1, d2)

Here's the one that is working for me.

from datetime import datetime

date_format = "%H:%M:%S"

# You could also pass datetime.time object in this part and convert it to string.
time_start = str('09:00:00') 
time_end = str('18:00:00')

# Then get the difference here.    
diff = datetime.strptime(time_end, date_format) - datetime.strptime(time_start, date_format)

# Get the time in hours i.e. 9.60, 8.5
result = diff.seconds / 3600;

Hope this helps!