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The special syntax *args in function definitions in python is used to pass a variable number of arguments to a function. It is used to pass a non-key worded, variable-length argument list. The syntax is to use the symbol * to take in a variable number of arguments; by convention, it is often used with the word args.
You can send any data types of argument to a function (string, number, list, dictionary etc.), and it will be treated as the same data type inside the function.
It exists, but it's hard to search for. I think most people call it the "splat" operator.
It's in the documentation as "Unpacking argument lists".
You'd use it like this: foo(*values). There's also one for dictionaries:
d = {'a': 1, 'b': 2}
def foo(a, b):
pass
foo(**d)
You should use the * operator, like foo(*values) Read the Python doc unpackaging argument lists.
Also, do read this: http://www.saltycrane.com/blog/2008/01/how-to-use-args-and-kwargs-in-python/
def foo(x,y,z):
return "%d, %d, %d" % (x,y,z)
values = [1,2,3]
# the solution.
foo(*values)
Try the following:
foo(*values)
This can be found in the Python docs as Unpacking Argument Lists.
That can be done with:
foo(*values)
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