Is there a bash command that takes as input a file path and returns an absolute file path? More specifically I would like a command that takes as input a path such as:
/tmp/yaneeve/kit/linux/../../output/kit/SOURCES//usr//apps/myapp/lib
and returns the path:
/tmp/yaneeve/output/kit/SOURCES/usr/apps/myapp/lib
Thanks!
In order to check if a directory exists in Bash using shorter forms, specify the “-d” option in brackets and append the command that you want to run if it succeeds. [[ -d <directory> ]] && echo "This directory exists!" [ -d <directory> ] && echo "This directory exists!"
In bash, there are a number of ways of retrieving the full address of a script. In particular, we can use realpath, readlink, or even create our custom little script. When we want to know the directory path, we can use the dirname command in our bash script to retrieve our directory path.
`eval` command is used in bash to execute arguments like a shell command. Arguments are joined in a string and taken as input for the shell command to execute the command. `eval` executes the command in the current shell.
eval is a built-in Linux command which is used to execute arguments as a shell command. It combines arguments into a single string and uses it as an input to the shell and execute the commands.
If the path exists, there is a portable way which is (even on linux) far more reliable:
canonicalPath=$(cd "$path"; pwd)
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