How to do Integer division in Dart?

Question

That is because Dart uses double to represent all numbers in dart2js. You can get interesting results, if you play with that:

Code:

int a = 1; 
a is int; 
a is double;

Result:

true
true

Actually, it is recommended to use type num when it comes to numbers, unless you have strong reasons to make it int (in for loop, for example). If you want to keep using int, use truncating division like this:

int a = 500;
int b = 250;
int c;

c = a ~/ b;

Otherwise, I would recommend to utilize num type.

Integer division is

c = a ~/ b;

you could also use

c = (a / b).floor();
c = (a / b).ceil();

if you want to define how fractions should be handled.

Short Answer

Use c = a ~/ b.

Long Answer

According to the docs, int are numbers without a decimal point, while double are numbers with a decimal point.

Both double and int are subtypes of num.

When two integers are divided using the / operator, the result is evaluated into a double. And the c variable was initialized as an integer. There are at least two things you can do:

1. Use c = a ~/ b.

The ~/ operator returns an int.

2. Use var c;. This creates a dynamic variable that can be assigned to any type, including a double and int and String etc.

Truncating division operator

You can use the truncating division operator ~/ to get an integer result from a division operation:

4 ~/ 2; // 2 (int)

Division operator

The regular division operator / will always return a double value at runtime (see the docs):

for (var i = 4; i == 4; i = 3) {
  i / 2; // 2 (double)
}

Runtime versus compile time

You might have noticed that I wrote a loop for the second example (for the regular division operator) instead of 4 / 2.

The reason for this is the following:
When an expression can be evaluated at compile time, it will be simplified at that stage and also be typed accordingly. The compiler would simply convert 4 / 2 to 2 at compile time, which is then obviously an int. The loop prevents the compiler from evaluating the expression.

As long as your division happens at runtime (i.e. with variables that cannot be predicted at compile time), the return types of the / (double) and ~/ (int) operators will be the types you will see for your expressions at runtime.

See this fun example for further reference.

Conclusion

Generally speaking, the regular division operator / always returns a double value and truncate divide can be used to get an int result instead.

Compiler optimization might, however, cause some funky results :)