How to create the "indexes" required for NSIndexPath:indexPathWithIndexes:length:

Question

The class method to create an index path with one or more nodes is:

+ (id)indexPathWithIndexes:(NSUInteger *)indexes length:(NSUInteger)length 

How do we create the "indexes" required in the first parameter?

The documentation listed it as Array of indexes to make up the index path but it is expecting a (NSUinteger *).

To create an index path of 1.2.3.4, is it simply an array of [1,2,3,4] ?

Answer 1

You are correct. You might use it like this:

NSUInteger indexArr[] = {1,2,3,4};  NSIndexPath *indexPath = [NSIndexPath indexPathWithIndexes:indexArr length:4];