How to convert Swift optional NSNumber to optional Int? (any improvements on my code?)

Question

What would be the shortest/cleanest way to convert an Optional Number to an Optional Int in Swift?

Is there a better way than this? (see below)

let orderNumberInt : Int?
if event.orderNum != nil {
    orderNumberInt = Int(event.orderNum!)
} else {
    orderNumberInt = nil
}

Answer 1

I think most easiest way is

var orderNumberInt = orderNum?.intValue

Also, you can do it like this

var orderNum:NSNumber? = NSNumber(int: 12)
var orderNumberInt:Int? = (orderNum != nil) ? Int(orderNum!) : nil
print(orderNumberInt)

Answer 2

let number:NSNumber? = NSNumber(integer: 125)


if let integerValue = number?.integerValue {
    print(integerValue)
}

let integerValue = number?.integerValue ?? 0

Answer 3

orderNumberInt = orderNum?.intValue

This is the best way to do it in Swift.

Reference: https://developer.apple.com/documentation/foundation/nsnumber/1412554-intvalue