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Input a comma - separated string using raw_input() method. Split the elements delimited by comma (,) and assign it to the list, to split string, use string. split() method. The converted list will contains string elements.
To convert string to list in Python, use the string split() method. The split() is a built-in Python method that splits the strings and stores them in the list.
In pyspark SQL, the split() function converts the delimiter separated String to an Array. It is done by splitting the string based on delimiters like spaces, commas, and stack them into an array. This function returns pyspark.
You can use the str.split method.
>>> my_string = 'A,B,C,D,E'
>>> my_list = my_string.split(",")
>>> print my_list
['A', 'B', 'C', 'D', 'E']
If you want to convert it to a tuple, just
>>> print tuple(my_list)
('A', 'B', 'C', 'D', 'E')
If you are looking to append to a list, try this:
>>> my_list.append('F')
>>> print my_list
['A', 'B', 'C', 'D', 'E', 'F']
In the case of integers that are included at the string, if you want to avoid casting them to int individually you can do:
mList = [int(e) if e.isdigit() else e for e in mStr.split(',')]
It is called list comprehension, and it is based on set builder notation.
ex:
>>> mStr = "1,A,B,3,4"
>>> mList = [int(e) if e.isdigit() else e for e in mStr.split(',')]
>>> mList
>>> [1,'A','B',3,4]
Consider the following in order to handle the case of an empty string:
>>> my_string = 'A,B,C,D,E'
>>> my_string.split(",") if my_string else []
['A', 'B', 'C', 'D', 'E']
>>> my_string = ""
>>> my_string.split(",") if my_string else []
[]
>>> some_string='A,B,C,D,E'
>>> new_tuple= tuple(some_string.split(','))
>>> new_tuple
('A', 'B', 'C', 'D', 'E')
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