Well, the best way is to use the following constructor:
template<class InputIterator> string (InputIterator begin, InputIterator end);
which would lead to something like:
std::vector<char> v;
std::string str(v.begin(), v.end());
I think you can just do
std::string s( MyVector.begin(), MyVector.end() );
where MyVector is your std::vector.
With C++11, you can do std::string(v.data())
or, if your vector does not contain a '\0'
at the end, std::string(v.data(), v.size())
.
std::string s(v.begin(), v.end());
Where v is pretty much anything iterable. (Specifically begin() and end() must return InputIterators.)
I like Stefan’s answer (Sep 11 ’13) but would like to make it a bit stronger:
If the vector ends with a null terminator, you should not use (v.begin(), v.end()): you should use v.data() (or &v[0] for those prior to C++17).
If v does not have a null terminator, you should use (v.begin(), v.end()).
If you use begin() and end() and the vector does have a terminating zero, you’ll end up with a string "abc\0" for example, that is of length 4, but should really be only "abc".
Just for completeness, another way is std::string(&v[0])
(although you need to ensure your string is null-terminated and std::string(v.data())
is generally to be preferred.
The difference is that you can use the former technique to pass the vector to functions that want to modify the buffer, which you cannot do with .data().
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