How to compare 2 folders' permission on Unix?

Question

Given 2 folder: /folder1 and /folder2 and each folder has some files and subfolders inside. I used following command to compare the file difference including sub folder :

diff -buf /folder1 /folder2

which found no difference in term of folder and file structural .

However, I found that there are some permission differences between these 2 folders' files. Is there simple way/command to compare the permission of each file under these 2 folders (including sub-folders) on Unix?

thanks,

Answer 1

If you have the tree command installed, it can do the job very simply using a similar procedure to the one that John C suggested:

cd a
tree -dfpiug > ../a.list
cd ../b
tree -dfpiug > ../b.list
cd ..
diff a.list b.list

Or, you can just do this on one line:

diff <(cd a; tree -dfpiug) <(cd b; tree -dfpiug)

The options given to tree are as follows:

• -d only scans directories (omit to compare files as well)
• -f displays the full path
• -p displays permissions (e.g., [drwxrwsr-x])
• -i removes tree's normal hierarchical indent
• -u displays the owner's username
• -g displays the group name