Is it like a regular python set?
Suppose I have the following queryset
entry_set = Entry.objects.all()
How do I check if Entry Object e is present in entry_set?
You can use exists() : if scorm. objects. filter(Header__id=qp.id).
In Django, we can use the id__in query with a queryset to filter down a queryset based on a list of IDs. However, by default this will fail if your IDs are UUIDs.
You can use the following code:
if e in Entry.objects.all(): #do something
Or the best approach:
if Entry.objects.filter(id=e.id).exists(): #do something
The best approach, according to Django documentation: https://docs.djangoproject.com/en/2.1/ref/models/querysets/#exists
if Entry.objects.filter(id=item.id).exists(): # Do something
But you can also do:
if item in Entry.objects.all(): # Do something
Although this approach is the worser as possible. Because it will loop over the whole Queryset pulling elements from the database one by one, compared to the other approach that is almost everything done in the Database level.
If you have a list of ids or a Queryset others approaches would be use __in
Example with a Queryset:
query_ids = other_queryset.values_list('field_id', flat=True) if Entry.objects.filter(id__in=query_ids).exists(): # Do something
Or if you have a list of ids:
if Entry.objects.filter(id__in=[1, 2, 3, 4, 5]).exists(): # Do something
Keep in mind that every time that you do len(queryset)
, item in queryset
or list(queryset)
you decrees heavily the performance of Django. I already see cases where by avoiding this practices We improved dozens of seconds in an application.
You can use in
operator:
entry_set = Entry.objects.all()
if an_entry in entry_set:
# The element present.
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