I have a cell array c
of equal-sized arrays, i.e. size(c{n}) = [ m l ... ]
for any n
. How can I get the mean
values (averaging over the cell array index n
) for all array elements in one sweep? I thought about using cell2mat
and mean
but the former does not add another dimension but changes l
to l*n
. And looping manually of course takes like forever...
If all of your arrays are the same size, it makes more sense to store them in a matrix rather than a cell array. That makes it easier to perform operations across them, like taking the mean. You can convert your data to a matrix using the functions NDIMS and CAT:
dim = ndims(c{1}); %# Get the number of dimensions for your arrays
M = cat(dim+1,c{:}); %# Convert to a (dim+1)-dimensional matrix
meanArray = mean(M,dim+1); %# Get the mean across arrays
If you have a Higher version of matlab, It can be done by 'cellfun' function. This can treat the cells with unequal size array.
C = {1:10, [2; 4; 6], []};
Cmeans = cellfun(@mean, C)
Cmeans =
5.5000 4.0000 NaN
Reference: https://groups.google.com/forum/?fromgroups=#!topic/comp.soft-sys.matlab/S_hyHxy11f0
You're on the right track. Use CELL2MAT to convert your cell array to a numerical array and then RESHAPE to construct a three dimensional matrix. You can then calculate the mean using the MEAN function with the dimension argument:
>> c = {[1 2 3; 4 5 6] [7 8 9; 12 13 14]} c = [2x3 double] [2x3 double] >> mean(reshape(cell2mat(c), [2, 3, 2]), 3) ans = 4 5 6 8 9 10
I found an easy way to find the mean values within a Cell array on the following link: http://www.gomatlab.de/cellfun-t25114.html
May x
be the cell. Then:
var_mean = cellfun(@mean, x, 'UniformOutput', false); %columnwise mean value
var_mean = cellfun(@(in) mean(in(:)), x); %% mean value of the total "subcell"
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