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How to add Headers on RESTful call using Jersey Client API

Here is the Format for RESTful call:

HEADERS:
    Content-Type: application/json;charset=UTF-8
    Authorization: Bearer Rc7JE8P7XUgSCPogjhdsVLMfITqQQrjg

REQUEST:
    GET https://api.example.com/1/realTime?json={"selection":{"includeAlerts":"true","selectionType":"registered","selectionMatch":"","isTheEvent":"true","includeRuntime":"true"}}

Here is my codes:

                try
                {
                 Client client = Client.create();
                 WebResource webResource = 
                         client.resource("https://api.example.com/1/realTime?json=
                         {"selection":{"includeAlerts":"true","selectionType":"registered","selectionMatch":"","isTheEvent":"true","includeRuntime":"true"}}");

                 //add header:Content-Type: application/json;charset=UTF-8
                 webResource.setProperty("Content-Type", "application/json;charset=UTF-8");

                 //add header: Authorization Bearer Rc7JE8P7XUgSCPogsdfdLMfITqQQrjg
                 value = "Bearer " + value;
                 webResource.setProperty("Authorization", value);

                 MultivaluedMap<String, String> queryParams = new MultivaluedMapImpl();
                 queryParams.add("json", js);

                 //Get response from RESTful Server
                 jsonStr = webResource.get(String.class);
                 System.out.println("Testing:");
                 System.out.println(jsonStr);

                }
                catch (Exception e)
                {
                  System.out.println (e.getMessage());
                  e.printStackTrace();
                  System.exit(0);
                }

But it returns error

com.sun.jersey.api.client.UniformInterfaceException: GET https://api.example.com/1/realTime? returned a response status of 500
    at com.sun.jersey.api.client.WebResource.handle(WebResource.java:607)
    at com.sun.jersey.api.client.WebResource.get(WebResource.java:187)
    at net.yorkland.restful.GetThermostatlist.GetThermostats(GetThermostatlist.java:60)

I think I didn't add headers correctly.

Can someone help me to fix it? Please give me advice how to add headers on request.

Thank you

like image 401
Eric Avatar asked Aug 20 '13 18:08

Eric


People also ask

How do I add a header to Jersey client?

The most straightforward way to define a header is calling WebTarget#request to obtain an Invocation. Builder that provides the header method.

How do I pass a header in REST API?

You can pass duplicate headers as well and there will not be any overwritten of values. For example, If we pass two values of header1 as value1 and value2 then it will be merged and will be passed as header1=value1 and header1=value2. It is the default behaviour.

What is jersey client?

Jersey is an open source framework for developing RESTFul Web Services. It also has great inbuilt client capabilities.


3 Answers

I use the header(name, value) method and give the return to webResource var:

Client client = Client.create();
WebResource webResource = client.resource("uri");

MultivaluedMap<String, String> queryParams = new MultivaluedMapImpl();
queryParams.add("json", js); //set parametes for request

appKey = "Bearer " + appKey; // appKey is unique number

//Get response from RESTful Server get(ClientResponse.class);
ClientResponse response = webResource.queryParams(queryParams)
    .header("Content-Type", "application/json;charset=UTF-8")
    .header("Authorization", appKey)
    .get(ClientResponse.class);

String jsonStr = response.getEntity(String.class);
like image 169
Eric Avatar answered Oct 24 '22 00:10

Eric


I think you're looking for header(name,value) method. See WebResource.header(String, Object)

Note it returns a Builder though, so you need to save the output in your webResource var.

like image 20
TheArchitect Avatar answered Oct 24 '22 00:10

TheArchitect


Try this!

Client client = ClientBuilder.newClient();

String jsonStr = client
            .target("http:....")
            .request(MediaType.APPLICATION_JSON)

            .header("WM_SVC.NAME", "RegistryService")
            .header("WM_QOS.CORRELATION_ID", "d1f0c0d2-2cf4-497b-b630-06d609d987b0")

            .get(String.class);

P.S You can add any number of headers like this!

like image 18
Sanchit Singhania Avatar answered Oct 24 '22 00:10

Sanchit Singhania