Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

How to add a class with React.js?

People also ask

Can I use class in react JS?

React class based components are the bread and butter of most modern web apps built in ReactJS. These components are simple classes (made up of multiple functions that add functionality to the application). All class based components are child classes for the Component class of ReactJS.

How do I add a class in React dynamically?

Use Native JavaScript to Set Dynamic className Values in React. The simplest way to add dynamic className values is to combine curly braces and set the className attributes equal to the state variables. This is a fairly simple feature available in all versions of JavaScript.


It is simple. take a look at this

https://codepen.io/anon/pen/mepogj?editors=001

basically you want to deal with states of your component so you check the currently active one. you will need to include

getInitialState: function(){}
//and 
isActive: function(){}

check out the code on the link


this is pretty useful:

https://github.com/JedWatson/classnames

You can do stuff like

classNames('foo', 'bar'); // => 'foo bar'
classNames('foo', { bar: true }); // => 'foo bar'
classNames({ 'foo-bar': true }); // => 'foo-bar'
classNames({ 'foo-bar': false }); // => ''
classNames({ foo: true }, { bar: true }); // => 'foo bar'
classNames({ foo: true, bar: true }); // => 'foo bar'

// lots of arguments of various types
classNames('foo', { bar: true, duck: false }, 'baz', { quux: true }); // => 'foo bar baz quux'

// other falsy values are just ignored
classNames(null, false, 'bar', undefined, 0, 1, { baz: null }, ''); // => 'bar 1'

or use it like this

var btnClass = classNames('btn', this.props.className, {
  'btn-pressed': this.state.isPressed,
  'btn-over': !this.state.isPressed && this.state.isHovered
});

Taken from their site.

render() {
  let className = 'menu';
  if (this.props.isActive) {
    className += ' menu-active';
  }
  return <span className={className}>Menu</span>
}

https://reactjs.org/docs/faq-styling.html


Since you already have <Tags> component calling a function on its parent, you do not need additional state: simply pass the filter to the <Tags> component as a prop, and use this in rendering your buttons. Like so:

Change your render function inside your <Tags> component to:

render: function() {
  return <div className = "tags">
    <button className = {this._checkActiveBtn('')} onClick = {this.setFilter.bind(this, '')}>All</button>
    <button className = {this._checkActiveBtn('male')} onClick = {this.setFilter.bind(this, 'male')}>male</button>
    <button className = {this._checkActiveBtn('female')} onClick = {this.setFilter.bind(this, 'female')}>female</button>
    <button className = {this._checkActiveBtn('blonde')} onClick = {this.setFilter.bind(this, 'blonde')}>blonde</button>
  </div>
},

And add a function inside <Tags>:

_checkActiveBtn: function(filterName) {
  return (filterName == this.props.activeFilter) ? "btn active" : "btn";
}

And inside your <List> component, pass the filter state to the <tags> component as a prop:

return <div>
  <h2>Kids Finder</h2> 
  <Tags filter = {this.state.filter} onChangeFilter = {this.changeFilter} />
  {list}
</div>

Then it should work as intended. Codepen here (hope the link works)


you can also use pure js to accomplish this like the old ways with jquery

try this if you want a simple way

 document.getElementById("myID").classList.add("show-example");