I have an array like [A,B,C,D]
. I want to access that array within a for loop like as
var arr = [A,B,C,D];
var len = arr.len;
for(var i = 0;i<arr.len;i++){
0 - A,B,C
1 - B,C,D
2 - C,D,A
3 - D,A,B
}
I want to access that like in JavaScript, any ideas?
Answering to the main question, someone can access an array in a circular manner using modular arithmetic. That can be achieved in JavaScript with the modulus operator (%
) and a workaround.
Given an array arr
of a length n
and a value val
stored in it that will be obtained through an access index i
, the circular manner, and safer way, to access the array, disregarding the value and sign of i
, would be:
let val = arr[(i % n + n) % n];
This little trick is necessary -- someone can not use the modulus result straightforwardly -- because JavaScript always evaluates a modulus operation as the remainder of the division between dividend (the first operand) and divisor (the second operand) disconsidering their signs but assigning to the remainder the sign of the dividend. That behavior does not always result in the desired "wrap around" effect of the modular arithmetic and could result in a wrong access of a negative position of the array.
References for more information:
Try this:
var arr = ["A","B","C","D"];
for (var i=0, len=arr.length; i<len; i++) {
alert(arr.slice(0, 3).join(","));
arr.push(arr.shift());
}
Without mutating the array, it would be
for (var i=0, len=arr.length; i<len; i++) {
var str = arr[i];
for (var j=1; j<3; j++)
str += ","+arr[(i+j)%len]; // you could push to an array as well
alert(str);
}
// or
for (var i=0, len=arr.length; i<len; i++)
alert(arr.slice(i, i+3).concat(arr.slice(0, Math.max(i+3-len, 0)).join(","));
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