What is the correct way to change the levels of a factor
column in a data.table
(note: not data frame)
library(data.table) mydt <- data.table(id=1:6, value=as.factor(c("A", "A", "B", "B", "B", "C")), key="id") mydt[, levels(value)] [1] "A" "B" "C"
I am looking for something like:
mydt[, levels(value) <- c("X", "Y", "Z")]
But of course, the above line does not work.
# Actual # Expected result > mydt > mydt id value id value 1: 1 A 1: 1 X 2: 2 A 2: 2 X 3: 3 B 3: 3 Y 4: 4 B 4: 4 Y 5: 5 B 5: 5 Y 6: 6 C 6: 6 Z
One way to change the level order is to use factor() on the factor and specify the order directly. In this example, the function ordered() could be used instead of factor() .
How do I Rename Factor Levels in R? The simplest way to rename multiple factor levels is to use the levels() function. For example, to recode the factor levels “A”, “B”, and “C” you can use the following code: levels(your_df$Category1) <- c("Factor 1", "Factor 2", "Factor 3") .
The number of levels of a factor or independent variable is equal to the number of variations of that factor that were used in the experiment. If an experiment compared the drug dosages 50 mg, 100 mg, and 150 mg, then the factor "drug dosage" would have three levels: 50 mg, 100 mg, and 150 mg.
Factors are the variables that experimenters control during an experiment in order to determine their effect on the response variable. A factor can take on only a small number of values, which are known as factor levels.
You can still set them the traditional way:
levels(mydt$value) <- c(...)
This should be plenty fast unless mydt
is very large since that traditional syntax copies the entire object. You could also play the un-factoring and refactoring game... but no one likes that game anyway.
To change the levels by reference with no copy of mydt
:
setattr(mydt$value,"levels",c(...))
but be sure to assign a valid levels vector (type character
of sufficient length) otherwise you'll end up with an invalid factor (levels<-
does some checking as well as copying).
I would rather go the traditional way of re-assignment to the factors
> mydt$value # This we what we had originally [1] A A B B B C Levels: A B C > levels(mydt$value) # just checking the levels [1] "A" "B" "C" **# Meat of the re-assignment** > levels(mydt$value)[levels(mydt$value)=="A"] <- "X" > levels(mydt$value)[levels(mydt$value)=="B"] <- "Y" > levels(mydt$value)[levels(mydt$value)=="C"] <- "Z" > levels(mydt$value) [1] "X" "Y" "Z" > mydt # This is what we wanted id value 1: 1 X 2: 2 X 3: 3 Y 4: 4 Y 5: 5 Y 6: 6 Z
As you probably notices, the meat of the re-assignment is very intuitive, it checks for the exact level
(use grepl
in case there's a fuzzy math, regular expressions or likewise)
levels(mydt$value)[levels(mydt$value)=="A"] <- "X"
This explicitly checks the value in the levels
of the variable under consideration and then reassigns X
(and so on) to it - The advantage- you explicitly KNOW what labeled what.
I find renaming levels as here levels(mydt$value) <- c("X","Y","Z")
very non-intuitive, since it just assigns X
to the 1st level it SEES in the data (so the order really matters)
PPS : In case of too many levels, use looping constructs.
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