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How does Bash parameter expansion work? [duplicate]

Tags:

syntax

bash

shell

I'm trying to understand a Bash script. I stumbled upon this:

DIR=${1:-"/tmp"}

What does that mean?

like image 967
user469083 Avatar asked Oct 07 '10 12:10

user469083


2 Answers

:- is actually an operator it says that if $1 (first argument to the script) is not set or is null then use /tmp as the value of $DIR and if it's set assign it's value to $DIR.

DIR=${1:-"/tmp"}

is short for

if [ -z $1 ]; then
        DIR='/tmp'
else
        DIR="$1"
fi

It can be used with any variables not just positional parameters:

$ echo ${HOME:-/tmp} # since $HOME is set it will be displayed.
/home/codaddict
$ unset HOME   # unset $HOME.
$ echo ${HOME:-/tmp} # since $HOME is not set, /tmp will be displayed.
/tmp
$ 
like image 145
codaddict Avatar answered Nov 06 '22 02:11

codaddict


That syntax is parameter expansion:

${parameter:-word}  

If parameter is unset or null, the expansion of word is substituted. Otherwise, the value of parameter is substituted.

So if $1 is unset or null, it evaluates to "/tmp" and to the value of $1 otherwise.

like image 24
Gumbo Avatar answered Nov 06 '22 01:11

Gumbo