How do you declare a Func with an anonymous return type?

Question

I need to be able to do this:

var getHed = () =>  {     // do stuff     return new { Property1 = value, Property2 = value2, etc...}; };  var anonymousClass = getHed(); 

But I get an error which indicates I need to explicitly declare getHed.

How do I declare Func such that T is the anonymous type I am returning?

In case you are curious why I need to do this, it is because I am using 3rd party software that allows customization code, but only within a single method. This can become very difficult to manage. I had the idea that I could use anonymous methods to help keep the procedural code organized. In this case, for it to help, I need a new class, which I cannot define except anonymously.

Answer 1

As is basically always the case with anonymous types, the solution is to use a generic method, so that you can use method type inference:

public static Func<TResult> DefineFunc<TResult>(Func<TResult> func) {     return func; } 

You can now write:

var getHed = DefineFunc(() =>  {     // do stuff     return new { Property1 = value, Property2 = value2, etc...}; });