How do I write a cpp __DIR__ macro, similar to __FILE__

Question

The __FILE__ and __LINE__ macros are built into the C Pre-Processor, and are often used for printing debug output with file names and line numbers. I need something similar, but with just the name of the directory at the end of the path. For instance if my code is in: /home/davidc/some/path/to/some/code/foo/bar I need a macro that will just give me "bar", if the code is in /home/davidc/some/path/to/some/code/foo/bee then I need it to give me "bee".

Any thoughts? (btw, this is for a C++ application).

Update: to be clear, I'm after a macro that will give me a string containing the directory name at compile-time, I don't want to do any string-processing at runtime.

Answer 1

If you are using GNU make to build your project, then you might be able to do something like this:

%.o: %.cpp
    $(CC) $(CFLAGS) -D__DIR__="$(strip $(lastword $(subst /, , $(dir $(abspath $<)))))" -c $< -o $@

That has to be about the most God-awful thing that I have thought about doing in a Makefile in quite a while. I don't think that you will find a quick or clean way to do this within the confines of the compiler so I'd look for clever ways to inject the information into the compilation process.

Good luck.