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I have a flat file where I have multiple occurrences of strings that contains single quote, e.g. hari's and leader's.
I want to replace all occurrences of the single quote with space, i.e.
hari's to hari s leader's to leader s I tried
sed -e 's/"'"/ /g' myfile.txt and
sed -e 's/"'"/" "/g' myfile.txt but they are not giving me the expected result.
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Just use " for the outer quotes in your sed and you can then use ' in the replacement. You don't want "+ unless you might have more than one consecutive " and you want to replace all of them. If you do, use sed -r "s/\\\"+/\\'/g" .
Use the String. replace() method to replace single with double quotes, e.g. const replaced = str. replace(/'/g, " ); . The replace method will return a new string where all occurrences of single quotes are replaced with double quotes.
You need to escape the special characters with a backslash \ in front of the special character. For your case, escape every special character with backslash \ .
Replacing all the occurrence of the pattern in a line : The substitute flag /g (global replacement) specifies the sed command to replace all the occurrences of the string in the line. Output : linux is great os.
Try to keep sed commands simple as much as possible. Otherwise you'll get confused of what you'd written reading it later.
#!/bin/bash sed "s/'/ /g" myfile.txt This will do what you want to
echo "hari's"| sed 's/\x27/ /g' It will replace single quotes present anywhere in your file/text. Even if they are used for quoting they will be replaced with spaces. In that case(remove the quotes within a word not at word boundary) you can use the following:
echo "hari's"| sed -re 's/(\<.+)\x27(.+\>)/\1 \2/g' HTH
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