I am implementing a small program that evaluates the Collatz conjecture. As part of this, I have a function that I call recursively that I want to store the current number being evaluated, determine if it is is a odd or even (or terminate if its just a 1), perform that branch of the conjecture and then call itself with the new number.
To do this, I wanted to pass a vector into this function and push the current number onto that vector, but I am having a tough time understanding how to pass a mutable vector reference.
Here is the code that I have:
fn evaluate_conjecture(number_to_be_evaluated: u64, mut intermediate_results: &Vec<u64>) -> u64 {
intermediate_results.push(number_to_be_evaluated);
if number_to_be_evaluated == 1 {
0
} else if number_to_be_evaluated % 2 == 1 {
let odd_step_result = perform_odd_conjecture_step(number_to_be_evaluated);
evaluate_conjecture(odd_step_result, intermediate_results) + 1
} else {
let even_step_result = perform_even_conjecture_step(number_to_be_evaluated);
evaluate_conjecture(even_step_result, intermediate_results) + 1
}
}
fn perform_odd_conjecture_step(_: u64) -> u64 {
unimplemented!()
}
fn perform_even_conjecture_step(_: u64) -> u64 {
unimplemented!()
}
and here is relevant part of my main
fn main() {
let input_number = 42;
let mut _intermediate_results: Vec<u64>;
let number_of_steps = evaluate_conjecture(input_number, &_intermediate_results);
}
Here is the error I am getting
error[E0596]: cannot borrow `*intermediate_results` as mutable, as it is behind a `&` reference
--> src/main.rs:2:5
|
1 | fn evaluate_conjecture(number_to_be_evaluated: u64, mut intermediate_results: &Vec<u64>) -> u64 {
| --------- help: consider changing this to be a mutable reference: `&mut std::vec::Vec<u64>`
2 | intermediate_results.push(number_to_be_evaluated);
| ^^^^^^^^^^^^^^^^^^^^ `intermediate_results` is a `&` reference, so the data it refers to cannot be borrowed as mutable
How do I pass this vector into the function so I can modify it each time the function is called?
Ultimate Rust Course: 7 Hours to Complete Rust Programming The main function invokes a function print_vector(). A vector is passed as parameter to this function. The ownership of the vector is also passed to the print_vector() function from the main().
Mutable data can be mutably borrowed using &mut T . This is called a mutable reference and gives read/write access to the borrower.
In order to initialize a vector via the new() method call, we use the double colon operator: let mut vec = Vec::new(); This call constructs a new, empty Vec<T> . The vector will not allocate until elements are pushed onto it.
&T
is an immutable reference.
&mut T
is a mutable reference.
Change your &Vec<u64>
to &mut Vec<u64>
and your &_intermediate_results
to &mut _intermediate_results
.
This is a thing which is fairly well documented; I suggest you read the documentation if you haven’t — it explains quite a lot. There's a section specifically about mutable references.
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