How do I parse URL params after a hash with Angularjs?

Question

I'm trying to parse for the access_token from Foursquare where the URL is like this:

https://mywebsite.com/4sqredirect/#access_token=1234567890XXXXX

I've tried $routeParams and $location and get nothing returned. Only after I tried $route, I did get an object back with the following attribute in it:

current:  { 
    params:  {  } 
    pathParams:  {  } 
    loadedTemplateUrl: partials/4sqredirect
    locals:  {  } 
    scope:  { 
        this:  { 
            $ref: $["current"]["scope"]
        } 
        route:  { 
            $ref: $
        } 
        location:  {  } 
        token: null
    }
} 

Does this mean there's no way to get it using native AngularJS functions cause of the hash?

UPDATE:

my controller looks like as follows:

angular.module('myApp')
    .controller('4sqredirectCtrl', function ($scope, $route, $location, $routeParams) {
        $scope.route = $route;
        $scope.location = $location;
        $scope.token = $routeParams.access_token;
    });

my main js looks like as follows:

angular.module('myApp', [
    'ngCookies',
    'ngResource',
    'ngSanitize',
    'ngRoute'
])
.config(function ($routeProvider, $locationProvider) {
    $locationProvider.html5Mode(true);

    $routeProvider
    .when('/', {
        templateUrl: 'partials/main',
        controller: 'MainCtrl'
    })
    .when('/4sqredirect/', {
        templateUrl: 'partials/4sqredirect',
        controller: '4sqredirectCtrl'
    })
    .otherwise({
        redirectTo: '/'
    });
});

Answer 1

From angular location service $location.hash() method return #after-hash

so if your url is look like

https://mywebsite.com/4sqredirect/#access_token=1234567890XXXXX 

then

$location.hash() return access_token=1234567890XXXXX

you need to split it split('=')[1]

see this plunker when you click 4Square then $location.url() return

/4sqredirect/#access_token=123456 $location.hash().split('=')[1] 

return 123456

Answer 2

Use $location.search()

//e.g. url https://www.example.com/#!?name=123
var s = $location.search();
// {name: '123'}

http://docs.angularjs.org/api/ng.$location

Search:

Returns search part (as object) of current url when called without any parameter.