PHP 5.4: Getting Fully-qualified class name of an instance variable

Question

I know there is a static class field on PHP 5.5, but I have to stick to PHP 5.4. Is it possible to get the fully qualified class name from a variable?

Example:

namespace My\Awesome\Namespace  class Foo {  } 

And somewhere else in the code:

public function bar() {    $var = new \My\Awesome\Namespace\Foo();     // maybe there's something like this??    $fullClassName = get_qualified_classname($var);     // outputs 'My\Awesome\Namespace\Foo'    echo $fullClassName  } 

Answer 1

You should be using get_class

If you are using namespaces this function will return the name of the class including the namespace, so watch out if your code does any checks for this.

namespace Shop;   <?php  class Foo  {    public function __construct()    {       echo "Foo";    }  }   //Different file   include('inc/Shop.class.php');   $test = new Shop\Foo();  echo get_class($test);//returns Shop\Foo  

This is a direct copy paste example from here