I have a generics class, Foo<T>
. In a method of Foo
, I want to get the class instance of type T
, but I just can't call T.class
.
What is the preferred way to get around it using T.class
?
The short answer is, that there is no way to find out the runtime type of generic type parameters in Java. I suggest reading the chapter about type erasure in the Java Tutorial for more details. A popular solution to this is to pass the Class of the type parameter into the constructor of the generic type, e.g.
To update the Box class to use generics, you create a generic type declaration by changing the code "public class Box" to "public class Box<T>". This introduces the type variable, T, that can be used anywhere inside the class. As you can see, all occurrences of Object are replaced by T.
Cannot Instantiate Generic Types with Primitive Types. Cannot Create Instances of Type Parameters.
The short answer is, that there is no way to find out the runtime type of generic type parameters in Java. I suggest reading the chapter about type erasure in the Java Tutorial for more details.
A popular solution to this is to pass the Class
of the type parameter into the constructor of the generic type, e.g.
class Foo<T> { final Class<T> typeParameterClass; public Foo(Class<T> typeParameterClass) { this.typeParameterClass = typeParameterClass; } public void bar() { // you can access the typeParameterClass here and do whatever you like } }
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