Use the JavaScript function JSON. stringify() to convert it into a string. const myJSON = JSON. stringify(obj);
It looks like you are passing an NSString
parameter where you should be passing an NSData
parameter:
NSError *jsonError;
NSData *objectData = [@"{\"2\":\"3\"}" dataUsingEncoding:NSUTF8StringEncoding];
NSDictionary *json = [NSJSONSerialization JSONObjectWithData:objectData
options:NSJSONReadingMutableContainers
error:&jsonError];
NSData *data = [strChangetoJSON dataUsingEncoding:NSUTF8StringEncoding];
NSDictionary *jsonResponse = [NSJSONSerialization JSONObjectWithData:data
options:kNilOptions
error:&error];
For example you have a NSString
with special characters in NSString
strChangetoJSON.
Then you can convert that string to JSON response using above code.
I've made a category from @Abizern answer
@implementation NSString (Extensions)
- (NSDictionary *) json_StringToDictionary {
NSError *error;
NSData *objectData = [self dataUsingEncoding:NSUTF8StringEncoding];
NSDictionary *json = [NSJSONSerialization JSONObjectWithData:objectData options:NSJSONReadingMutableContainers error:&error];
return (!json ? nil : json);
}
@end
Use it like this,
NSString *jsonString = @"{\"2\":\"3\"}";
NSLog(@"%@",[jsonString json_StringToDictionary]);
With Swift 3 and Swift 4, String
has a method called data(using:allowLossyConversion:)
. data(using:allowLossyConversion:)
has the following declaration:
func data(using encoding: String.Encoding, allowLossyConversion: Bool = default) -> Data?
Returns a Data containing a representation of the String encoded using a given encoding.
With Swift 4, String
's data(using:allowLossyConversion:)
can be used in conjunction with JSONDecoder
's decode(_:from:)
in order to deserialize a JSON string into a dictionary.
Furthermore, with Swift 3 and Swift 4, String
's data(using:allowLossyConversion:)
can also be used in conjunction with JSONSerialization
's jsonObject(with:options:)
in order to deserialize a JSON string into a dictionary.
With Swift 4, JSONDecoder
has a method called decode(_:from:)
. decode(_:from:)
has the following declaration:
func decode<T>(_ type: T.Type, from data: Data) throws -> T where T : Decodable
Decodes a top-level value of the given type from the given JSON representation.
The Playground code below shows how to use data(using:allowLossyConversion:)
and decode(_:from:)
in order to get a Dictionary
from a JSON formatted String
:
let jsonString = """
{"password" : "1234", "user" : "andreas"}
"""
if let data = jsonString.data(using: String.Encoding.utf8) {
do {
let decoder = JSONDecoder()
let jsonDictionary = try decoder.decode(Dictionary<String, String>.self, from: data)
print(jsonDictionary) // prints: ["user": "andreas", "password": "1234"]
} catch {
// Handle error
print(error)
}
}
With Swift 3 and Swift 4, JSONSerialization
has a method called jsonObject(with:options:)
. jsonObject(with:options:)
has the following declaration:
class func jsonObject(with data: Data, options opt: JSONSerialization.ReadingOptions = []) throws -> Any
Returns a Foundation object from given JSON data.
The Playground code below shows how to use data(using:allowLossyConversion:)
and jsonObject(with:options:)
in order to get a Dictionary
from a JSON formatted String
:
import Foundation
let jsonString = "{\"password\" : \"1234\", \"user\" : \"andreas\"}"
if let data = jsonString.data(using: String.Encoding.utf8) {
do {
let jsonDictionary = try JSONSerialization.jsonObject(with: data, options: []) as? [String : String]
print(String(describing: jsonDictionary)) // prints: Optional(["user": "andreas", "password": "1234"])
} catch {
// Handle error
print(error)
}
}
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