How do I deserialize a JSON array using Newtonsoft.Json

Question

[    {       "receiver_tax_id":"1002",       "total":"6949,15",       "receiver_company_name":"Das Company",       "receiver_email":"[email protected]",       "status":0    },    {       "receiver_tax_id":"1001",       "total":"39222,49",       "receiver_company_name":"SAD company",       "receiver_email":"[email protected]",       "status":1    } ] 

Hi, this is my Json data, but I can't deserialize it. I want to check only "status" value. (first object "status" 0, second object "status" 1).

Example definition:

public class Example  {     [JsonProperty("receiver_tax_id")]      public string receiver_tax_id { get; set; }     [JsonProperty("total")]      public string total { get; set; }     [JsonProperty("receiver_company_name")]      public string receiver_company_name { get; set; }     [JsonProperty("receiver_email")]      public string receiver_email { get; set; }     [JsonProperty("status")]      public int status { get; set; }  } 

Deserialization code:

var des = (Example)JsonConvert.DeserializeObject(responseString, typeof(Example));  Console.WriteLine(des.status[0].ToString()); 

Answer 1

Try this code:

public class Receiver  {    public string receiver_tax_id { get; set;}    public string total { get; set;}    public string receiver_company_name { get; set;}    public int status { get; set;} } 

And deserialize looks like follows:

var result = JsonConvert.DeserializeObject<List<Receiver>>(responseString); var status = result[0].status; 

Answer 2

If you only care about checking status you can use the dynamic type of .NET (https://msdn.microsoft.com/en-us/library/dd264741.aspx)

dynamic deserialized = JObject.Parse(responseString);  int status1 = deserialized[0].status;  int status2 = deserialized[1].status;  // // do whatever 

This way you don't even need the Example class.