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Getting "Handshake failed...unexpected packet format" when using WebClient.UploadFile() with "https" when the server has a valid SSL certificate

I am trying to use WebClient.UploadFile with a HTTPS URL but I am ending up with

"System.IO.IOException: The handshake failed due to an unexpected packet format"

The same code works perfectly fine with Http but the server that I am trying to hit has a perfectly fine ssl certificate. Here is anything relevant to the web call:

var url = WebServiceCommunication.GetProtocolName() + "..."; //turns out to be     "https://... var wc = new WebClient(); //I am adding:  wc.Headers.Add(HttpRequestHeader.KeepAlive, "...") wc.Headers.Add(HttpRequestHeader.AcceptLanguage, "...") we.Headers.Add(HttpRequestHeader.Cookie, "...")  wc.UploadFile(url, "POST", filename); 

Is the issue with any of the HttpRequestHeaders I am adding AND using https with those? Or am I missing a necessary header if I want to use https? Does anyone have any pointers as to why this would work with HTTP but NOT HTTPS when the SSL cert is valid?

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user1867353 Avatar asked Jun 03 '13 11:06

user1867353


People also ask

How do I fix the handshake failed due to an unexpected packet format?

This usually happen if you connect to a webserver using https but the web server is not set up for https. Try to use http:// instead of https:// in the URL.

What does SSL handshake failed mean?

A TLS/SSL handshake failure occurs when a client and server cannot establish communication using the TLS/SSL protocol. When this error occurs in Apigee Edge, the client application receives an HTTP status 503 with the message Service Unavailable.


1 Answers

You have to make sure the port you are connecting to is port 443 instead of port 80.

Example of explicitly setting the port to be used in the URL:

var request = (HttpWebRequest) WebRequest.Create("https://example.com:443/"); request.Method = "GET"; request.UserAgent = "example/1.0"; request.Accept = "*/*"; request.Host = "example.com";  var resp = (HttpWebResponse) request.GetResponse(); 
like image 173
rene Avatar answered Sep 27 '22 21:09

rene