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I am working on a small code in bash, but I am stuck on a small problem.
I have a string, and I want to replace the last letter of that string with s.
For example: I am taking all the files that end in c and replacing the last c with s.
for file in *.c; do
# replace c with s
echo $file
Can someone please help me?
617
replace() method to replace the last character in a string, e.g. const replaced = str. replace(/. $/, 'replacement'); . The replace method will return a new string with the last character replaced by the provided replacement.
To replace one character in a string with another character, we can use the parameter extension in Bash (shell). Here is an example that removes the character a with b in the following string. Similarly, you can also replace multiple characters in the string with a single character like this.
You can also use the sed command to remove the characters from the strings. In this method, the string is piped with the sed command and the regular expression is used to remove the last character where the (.) will match the single character and the $ matches any character present at the end of the string.
To replace content in a file, you must search for the particular file string. The 'sed' command is used to replace any string in a file using a bash script. This command can be used in various ways to replace the content of a file in bash. The 'awk' command can also be used to replace the string in a file.
for file in *.c; do
echo "${file%?}s"
done
In parameter substitution, ${VAR%PAT} will remove the last characters matching PAT from variable VAR.
Shell patterns * and ? can be used as wildcards.
The above drops the final character, and appends "s".
161
Use parameter substitution. The following accomplishes suffix replacement. It replaces one instance of c anchored to the right with s.
for file in *.c; do
echo "${file/%c/s}"
done
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