My goal is to delegate method calls against my struct to a Trait's methods, where the Trait object is inside an Rc
of RefCell
.
I tried to follow the advice from this question: How can I obtain an &A reference from a Rc<RefCell<A>>?
I get a compile error.
use std::rc::Rc;
use std::cell::RefCell;
use std::fmt::*;
use std::ops::Deref;
pub struct ShyObject {
pub association: Rc<RefCell<dyn Display>>
}
impl Deref for ShyObject {
type Target = dyn Display;
fn deref<'a>(&'a self) -> &(dyn Display + 'static) {
&*self.association.borrow()
}
}
fn main() {}
Here is the error:
error[E0515]: cannot return value referencing temporary value
--> src/main.rs:13:9
|
13 | &*self.association.borrow()
| ^^-------------------------
| | |
| | temporary value created here
| returns a value referencing data owned by the current function
My example uses Display
as the trait; in reality I have a Trait with a dozen methods. I am trying to avoid the boilerplate of having to implement all those methods and just burrow down to the Trait object in each call.
You can't. RefCell::borrow
returns a Ref<T>
, not a &T
. If you try to do this in a method then you will need to first borrow the Ref<T>
but it will go out of scope.
Instead of implementing Deref
, you could have a method that returns something that does:
impl ShyObject {
fn as_deref(&self) -> impl Deref<Target = dyn Display> {
self.association.borrow()
}
}
Otherwise, since you only want to expose the Display
implementation of the inner data anyway, you can workaround it by actually dereferencing a different type which delegates:
pub struct ShyObject {
association: Assocation<dyn Display>,
}
struct Assocation<T: ?Sized>(Rc<RefCell<T>>);
impl<T: Display + ?Sized> fmt::Display for Assocation<T> {
fn fmt(&self, f: &mut fmt::Formatter) -> fmt::Result {
write!(f, "{}", self.0.borrow())
}
}
impl Deref for ShyObject {
type Target = dyn Display + 'static;
fn deref(&self) -> &Self::Target {
&self.association
}
}
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