How can i get the path from where gulp was run?

Question

I'm building a frontend workflow with gulp where i need to be able to build multiple separate designs but they need to share some common settings.

To clarify, i have a structure like this:

• [Project root]
  • Templates
    • Designs
      • MyDesign1
        • Assets
          • js
            • .js
          • scss
            • .scss
        • gulpfile.js
      • MyDesign2
        • Assets
          • js
            • .js
          • scss
            • .scss
        • gulpfile.js
      • [More designs can be added later]
  • .eslintrc (Shared)
  • sftp-config.json (Shared)

I'd like to be able to call gulp in templates/designs/mydesign1 or templates/designs/mydesign2 and have acess to the data inside [Project root]/sftp-config.json and [Project root]/.eslintrc and any other file that might exist outside of the folder that gulp was run from.

Is that possible?

Answer 1

I found a solution to my problem, and it seems to work pretty well for my needs:

By using process.cwd() i can get the folder that gulp ran in, and then i can use path.resolve('../') to step back in my folders until i hit my project root folder.

var gulpRanInThisFolder = process.cwd();
var rootDir = path.resolve('../','../','../','../');
var designFolderName = pkg.name;
var sftpConfigPath =  path.join(rootDir, '/sftp-config.json');