i have code written in nodejs make me confusying using Q Promises
theFunction()
.then(function(data) {
var deferred = Q.defer()
var result = [];
for(i=0; i < data.length; i++) {
secondFunc(data.item)
.then(function(data2) {
data.more = data2.item
});
result.push(data);
}
deferred.resolve(result);
deferred.promise();
});
i want data in second function inside loop can push into result
so my previous data is like this
[
{
id: 1,
item: 1,
hero: 2
},
{
id: 1,
item: 1,
hero: 2
}
]
and so like this
[
{
id: 1,
item: 1,
hero: 2,
more: {
list: 1
}
},
{
id: 1,
item: 1,
hero: 2,
more: {
list: 4
}
}
]
I've tried several ways start by entering the command deferred.resolve (); statement in the loop and only showing 1 data have any solution ?
Instead of a deferred.resolve()
on an array which will resolve immediately, use Q.all
which waits for an array of promises:
theFunction()
.then(function(data) {
var result = [];
for(var i=0; i < data.length; i++) (function(i){
result.push(secondFunc(data[i].item)
.then(function(data2) {
data[i].more = data2.item;
return data[i];
}));
})(i); // avoid the closure loop problem
return Q.all(result)
});
Or even better:
theFunction()
.then(function(data) {
return Q.all(data.map(function(item)
return secondFunc(item)
.then(function(data2) {
item.more = data2.item;
return item;
});
});
});
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