Possible Duplicate:
Caller function in PHP 5?
I would like to know from where a global function or public method is being called. I guess I could do it by inspecting debug_backtrace but I'd rather use a lighterweight mechanism if one exists. Any suggestions?
For example something like so, if you imagine the get_callee() function and constant existing:
function doSomething() {
if(get_callee() == 'PHP_GLOBAL') { throw new IllegalAccessException(); }
...
}
Edit: Sorry, saw your note about debug_backtrace() now.
Kinda ugly but hey, if you need to do this something is wrong.
The magic is in the get_callee() function and debug_backtrace(). And yes, add some error checking if you must use this.
<?php
init();
function foo()
{
echo 'bar called from ' . get_callee() . '<br />';
bar();
}
function bar()
{
echo 'foo called from ' . get_callee() . '<br />';
}
function init()
{
echo 'init.. <br />';
foo();
}
function get_callee()
{
$backtrace = debug_backtrace();
return $backtrace[1]['function'];
}
Outputs:
init..
bar called from foo
foo called from bar
Why dont you simply use OO and declare your method/function private?
If you start sprinkling those get_callee() all over your code, you are creating a horrible kludge.
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