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I have a well formed XHTML page. I want to find the destination URL of a link when I have the text that is linked.
Example
<a href="http://stackoverflow.com">programming questions site</a> <a href="http://cnn.com">news</a> I want an XPath expression such that if given programming questions site it will give http://stackoverflow.com and if I give it news it will give http://cnn.com.
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A linkText is used to identify the hyperlinks on a web page. It can be determined with the help of an anchor tag (<a>). In order to create the hyperlinks on a web page, you can use anchor tags followed by the linkText. Now, let's examine linkText locator with the help of an example.
This will get you the generic link: selenium. FindElement(By. XPath("xpath=//a[contains(@href,'listDetails.do')")).
Should be something similar to:
//a[text()='text_i_want_to_find']/@href
73
Too late for you, but for anyone else with the same question...
//a[contains(text(), 'programming')]/@href Of course, 'programming' can be any text fragment.
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