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Having a XML document like this:
<?xml version="1.0" encoding="UTF-8"?>
<records type="array">
<record>
<name>svn</name>
<record-type>A</record-type>
<ttl type="integer">86400</ttl>
<zone-id type="integer">69075</zone-id>
<aux type="integer">0</aux>
<id type="integer">xxx</id>
<active>Y</active>
<data>xxx.xxx.xxx.xxx</data>
</record>
<record>
<name>domain.tld.</name>
<record-type>NS</record-type>
<ttl type="integer">86400</ttl>
<zone-id type="integer">xxx</zone-id>
<aux type="integer">0</aux>
<id type="integer">xxx</id>
<active>Y</active>
<data>domain.tld.</data>
</record>
<record>
<name>blog</name>
<record-type>A</record-type>
<ttl type="integer">86400</ttl>
<zone-id type="integer">xxx</zone-id>
<aux type="integer">0</aux>
<id type="integer">xxx</id>
<active>Y</active>
<data>xxx.xxx.xxx.xxx</data>
</record>
</records>
How to match all the /records/record/name having as sibling /records/record/record-type with the value A?
287
Select all A sibling elements that precede the context node. > Select all A sibling elements that follow the context node. > Select all sibling elements that precede the context node. > Select the first preceding sibling element named A in reverse document order.
A Parent of a context node is selected Flat element. A string of elements is normally separated by a slash in an XPath statement. You can pick the parent element by inserting two periods “..” where an element would typically be. The parent of the element to the left of the double period will be selected.
Found it:
/records/record/name[../record-type/text() = "A"]
Surprisingly, none of the answers to date on this old question provide the simplest XPath solution.
This simple XPath
/records/record[record-type = "A"]/name
selects
<name>svn</name>
<name>blog</name>
as requested.
36
You can also filter a parent element by its children :
/records/record[record-type[text()='A']]/name
26
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