How can I escape white space in a bash loop list?

Question

First, don't do it that way. The best approach is to use find -exec properly:

# this is safe
find test -type d -exec echo '{}' +

The other safe approach is to use NUL-terminated list, though this requires that your find support -print0:

# this is safe
while IFS= read -r -d '' n; do
  printf '%q\n' "$n"
done < <(find test -mindepth 1 -type d -print0)

You can also populate an array from find, and pass that array later:

# this is safe
declare -a myarray
while IFS= read -r -d '' n; do
  myarray+=( "$n" )
done < <(find test -mindepth 1 -type d -print0)
printf '%q\n' "${myarray[@]}" # printf is an example; use it however you want

If your find doesn't support -print0, your result is then unsafe -- the below will not behave as desired if files exist containing newlines in their names (which, yes, is legal):

# this is unsafe
while IFS= read -r n; do
  printf '%q\n' "$n"
done < <(find test -mindepth 1 -type d)

If one isn't going to use one of the above, a third approach (less efficient in terms of both time and memory usage, as it reads the entire output of the subprocess before doing word-splitting) is to use an IFS variable which doesn't contain the space character. Turn off globbing (set -f) to prevent strings containing glob characters such as [], * or ? from being expanded:

# this is unsafe (but less unsafe than it would be without the following precautions)
(
 IFS=$'\n' # split only on newlines
 set -f    # disable globbing
 for n in $(find test -mindepth 1 -type d); do
   printf '%q\n' "$n"
 done
)

Finally, for the command-line parameter case, you should be using arrays if your shell supports them (i.e. it's ksh, bash or zsh):

# this is safe
for d in "$@"; do
  printf '%s\n' "$d"
done

will maintain separation. Note that the quoting (and the use of $@ rather than $*) is important. Arrays can be populated in other ways as well, such as glob expressions:

# this is safe
entries=( test/* )
for d in "${entries[@]}"; do
  printf '%s\n' "$d"
done

find . -type d | while read file; do echo $file; done

However, doesn't work if the file-name contains newlines. The above is the only solution i know of when you actually want to have the directory name in a variable. If you just want to execute some command, use xargs.

find . -type d -print0 | xargs -0 echo 'The directory is: '

Here is a simple solution which handles tabs and/or whitespaces in the filename. If you have to deal with other strange characters in the filename like newlines, pick another answer.

The test directory

ls -F test
Baltimore/  Cherry Hill/  Edison/  New York City/  Philadelphia/  cities.txt

The code to go into the directories

find test -type d | while read f ; do
  echo "$f"
done

The filename must be quoted ("$f") if used as argument. Without quotes, the spaces act as argument separator and multiple arguments are given to the invoked command.

And the output:

test/Baltimore
test/Cherry Hill
test/Edison
test/New York City
test/Philadelphia

This is exceedingly tricky in standard Unix, and most solutions run foul of newlines or some other character. However, if you are using the GNU tool set, then you can exploit the find option -print0 and use xargs with the corresponding option -0 (minus-zero). There are two characters that cannot appear in a simple filename; those are slash and NUL '\0'. Obviously, slash appears in pathnames, so the GNU solution of using a NUL '\0' to mark the end of the name is ingenious and fool-proof.

You could use IFS (internal field separator) temporally using :

OLD_IFS=$IFS     # Stores Default IFS
IFS=$'\n'        # Set it to line break
for f in `find test/* -type d`; do
    echo $f
done

IFS=$OLD_IFS

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