I am trying to write a program that removes a specific element from a string, but most of the things I use (like filter
) only work for [Char]
. I really just don't want to have to type "['h','e','l','l','o']"
instead of "hello"
. I realize that technically a String
is just a fancy [Char]
, but how would I unfancify it into a standard [Char]
. Also if you have another way to write normal words instead of in an array format please tell me.
We can convert String to char in java using charAt() method of String class. The charAt() method returns a single character only. To get all characters, you can use loop.
Strings can be converted to lists using list() .
To convert a string to list of characters in Python, use the list() method to typecast the string into a list. The list() constructor builds a list directly from an iterable, and since the string is iterable, you can construct a list from it.
So, let us explore the 7 different ways to achieve this conversion. The split method by default takes whitespace as delimiter and separates the words of the string from by the whitespace and converts them into a list. To convert a string into list of characters, we can simply use type conversion using the inbuilt list () method.
Alternatively, you can use the List constructor to initialize a new instance of the List<char> class with characters of a string. You can simply pass a string to the list constructor, as the following example illustrates: If you want a list of strings, then you would use a List<string> rather than List<char>.
Python | Program to convert String to a List. In this program, we will try to convert a given string to a list, where spaces or any other special characters, according to the users choice, are encountered. To do this we use the split() method. Syntax: Examples: The split method is used to split the strings and store them in the list.
To get a List<char>, do like: If you need a List<string> instead to store the characters, convert each character to a string first: 2. Using List Constructor Alternatively, you can use the List constructor to initialize a new instance of the List<char> class with characters of a string.
As was already said, String
is simply a synonym for [Char]
type String = [Char]
so both can be used interchangeably.
In particular, "hello" :: [Char]
is exactly the same as "hello" :: String
, both are just more elegant ways of writing ['h','e','l','l','o']
.
That said, you'll find that not everything that would be a “String” in other languages is a String
in Haskell. See, the list implementation is actually really inefficient in particular memory-wise – for an ASCII string, most languages take either 8 or 16 bit per character, but with Haskell's String
type each character is a 64-bit Char
plus a reference to the next character, for a total 128 bits!
That's why most modern Haskell libraries avoid String
, except for short things like file names. (Incidentally,
type FilePath = String
so that is also interchangeable.)
What these libraries use for general string is typically Text
, which is indeed a different type, corresponding more to other languages' implementations (it uses UTF-16 under the hood).
If you want to filter a value of that type, you can either convert it to a listy-String
with unpack
, or you can simply use the dedicated version of filter
provided by the text library.
In standard Haskell, Text
values can not be defined as string- or list literals, you'd need to explicitly wrap that like pack ['h','e','l','l','o']
. However they can still be defined with a simple string literal, provided that you turn on {-# LANGUAGE OverloadedStrings #-}
:
ghci> :m +Data.Text
ghci> "hello" :: Text
<interactive>:5:1: error:
• Couldn't match expected type ‘Text’ with actual type ‘[Char]’
• In the expression: "hello" :: Text
In an equation for ‘it’: it = "hello" :: Text
ghci> :set -XOverloadedStrings
ghci> "hello" :: Text
"hello"
With another extension, this also works for the list syntax:
ghci> ['h','e'] :: Text
<interactive>:9:1: error:
• Couldn't match expected type ‘Text’ with actual type ‘[Char]’
• In the expression: ['h', 'e'] :: Text
In an equation for ‘it’: it = ['h', 'e'] :: Text
ghci> :set -XOverloadedLists
ghci> ['h','e'] :: Text
"he"
In Haskell, the square brackets mean a list, as they also do in Python. Haskell also uses white space syntax.
You can tell what type a String is in Haskell by using :t in the ghci REPL.
:t "String" -- "String" :: [Char]
So a string, in double quotes, really is a list of characters.
How about a list of strings?
:t ["airplane","boat","car"] -- ["airplane","boat","car"] :: [[Char]]
So a list of strings is a list of lists of characters.
As for filtering, if I apply a filter to a string, it behaves exactly as a filter on a list of characters:
:m +Data.Char
filter isUpper "String" -- returns "S"
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