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A straightforward way to check the equality of the two lists in Python is by using the equality == operator. When the equality == is used on the list type in Python, it returns True if the lists are equal and False if they are not.
The difference between two lists (say list1 and list2) can be found using the following simple function. By Using the above function, the difference can be found using diff(temp2, temp1) or diff(temp1, temp2) . Both will give the result ['Four', 'Three'] .
Using Counter() , we usually are able to get frequency of each element in list, checking for it, for both the list, we can check if two lists are identical or not. But this method also ignores the ordering of the elements in the list and only takes into account the frequency of elements.
Just use the classic == operator:
>>> [0,1,2] == [0,1,2]
True
>>> [0,1,2] == [0,2,1]
False
>>> [0,1] == [0,1,2]
False
Lists are equal if elements at the same index are equal. Ordering is taken into account then.
If you want to just check if they are identical or not, a == b should give you true / false with ordering taken into account.
In case you want to compare elements, you can use numpy for comparison
c = (numpy.array(a) == numpy.array(b))
Here, c will contain an array with 3 elements all of which are true (for your example). In the event elements of a and b don't match, then the corresponding elements in c will be false.
The expression a == b should do the job.
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