How can I avoid printing anything in Bash `printf` with an empty array?

Question

I often print out the contents of an array using a quick printf shorthand like this:

$ printf "%s\n" "${my_array[@]}"
$ printf "%s\0" "${my_array[@]}"

This works great in general:

$ my_array=(limburger stilton wensleydale)
$ printf "%s\n" "${my_array[@]}"
limburger
stilton
wensleydale
$

Works great, but when the array is empty it still outputs a single character (a newline or null byte):

$ my_array=()
$ printf "%s\n" "${my_array[@]}"

$

Of course, I can avoid that by testing first for an empty array:

$ [[ ${#my_array[@]} -gt 0 ]] && printf "%s\n" "${my_array[@]}"
$ (( ${#my_array[@]} )) && printf "%s\n" "${my_array[@]}"

But I use this idiom all the time and would prefer to keep it as short as possible. Is there a better (shorter) solution, maybe a different printf format, that won't print anything at all with an empty array?

Answer 1

Bash's parameter expansion might help:

printf "%b" "${my_array[@]/%/\\n}"

From help printf:

%b: expand backslash escape sequences in the corresponding argument

or

printf "%s" "${my_array[@]/%/$'\n'}"

Answer 2

For what it is worth:

(( ${#my_array[@]} )) && printf "%s\n" "${my_array[@]}"

(( ${#my_array[@]} )) is a Bash's stand-alone arithmetic expression that evaluates to true when array length is greater than 0.

Anyway, when I need to debug the content of an array. I prefer to use:

declare -p my_array

It will clearly show details that a simple printf '%s\n' cannot, like:

• element key or index,
• empty elements,
• elements containing non-printable characters,
• all of variable type or flags,
• if array is undeclared, void declare -a my_array= or empty declare -a my_array=().