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Hiding private members of c++ library

I have written a library (doesn't matter what it does), which obviously has its header file. Now, I want to hide private elements of that header file, so if I provide my library to somebody, he/she should only see public members (preferably no class definition, nothing other than function definitions). One way would be creating C-style header, which will contain some kind of "init" method which will be used to create an instance of the actual class of library and the user will have to pass a pointer of that object to every function to do the job.

Is it a good practice?

Are there any other publicly accepted ways of doing something like that?

Thanks in advance.

like image 894
khajvah Avatar asked Jul 09 '13 17:07

khajvah


3 Answers

Base on Eric Finn's answer, you can just declare an interface class to hold all your public methods which considered to be your API, and hide all implementations and private members/methods in implementation class which inherits interface class, here's the example:

Your header file: my_api.h

// your API in header file
// my_api.h
class interface {
public:
    static interface* CreateInstance();
    virtual void draw() = 0;
    virtual void set(int) = 0;
};

your implementation(shared library): my_api.cpp (users won't see this when you make it a shared library) So you can hide all your implementation and private methods/members here

#include "my_api.h"
        // implementation -> in .cc file
class implementation : public interface {
    int private_int_;
    void ReportValue_();
public:
    implementation();
    void draw();
    void set(int new_int);
};

implementation::implementation() {
    // your actual constructor goes here
}

void implementation::draw() {
    cout << "Implementation class draws something" << endl;
    ReportValue_();
}

void implementation::ReportValue_() {
    cout << "Private value is: " << private_int_ << endl;
}
void implementation::set(int new_int) {
    private_int_ = new_int;
}
interface* interface::CreateInstance() {
    return new implementation;
}

How user uses your API:

#include <iostream>
#include "my_api.h"

int main(int argc, const char * argv[])
{

    using namespace std;
    interface* a; interface* b;
    a = interface::CreateInstance();
    a->set(1);
    b = interface::CreateInstance();
    b->set(2);
    b->draw();
    a->draw();
    return 0;
}

Output:

Implementation class draws
Private int is: 2
Implementation class draws
Private int is: 1    

In this pattern, your api is just an abstract class which works like a factory, you can also implement the virtual method in different classes and specify which instance you would like to call.

like image 114
Charles Chow Avatar answered Nov 01 '22 12:11

Charles Chow


In addition to the Factory pattern (which, in my opinion, can become unwieldy), you can also hide your private members behind a PIMPL (Pointer to IMPLementation):

// Interface.hpp
class Implementation;
class Interface {
public:
    Interface() : pimpl(new Implementation()) {}
    void publicMethod();
private:
    std::unique_ptr<Implementation> pimpl;
};

// Interface.cpp
class Implementation {
public:
    void PrivateMember();
};

void Interface::publicMethod() { pimpl->PrivateMember(); }

This has the advantage of hiding implementation, at the cost of a single pointer indirection, not much different from the typical inheritance-based Factory pattern.

This can also be ABI stable. Changes to your implementation won't affect linkage, since no changes will ever be visible to the rest of the program. This is a good pattern to use when implementing shared objects, for example.

It's also a common C++ idiom, so other C++ programmers will recognize it without question.

In the case of a class which will follow the Singleton pattern, you can avoid exposing the PIMPL at all, and simply write the entire implementation in an anonymous namespace in your .cpp file, where you can put as much state and private functions as you wish, without even hinting at it in your interface.

like image 40
greyfade Avatar answered Nov 01 '22 11:11

greyfade


You can create a publicly-visible interface. Create an abstract class with the functions you want to expose, then have your implementation extend it.

For example, an interface:

class Interface {
public:
    virtual void publicMethod() = 0;
...
};

And the implementation:

class Implementation : Interface {
public:
    virtual void publicMethod();
private:
    int hiddenMethod();
};

Then you only export the symbols for Interface. Now, in order for the user of the library to get instances of Interface which are actually Implementations, you need to provide a factory:

class Factory {
public:
    //can create and return an Implementation pointer, but caller will get an Interface pointer
    std::shared_ptr<Interface> getImplementationInstance();
}
like image 26
Eric Finn Avatar answered Nov 01 '22 13:11

Eric Finn