I have written some code in which a small part of the code takes a large one dimensional Unboxed.Vector and returns them as a Vector (Vector a).
A part of the code is giving an error. Here is a sample piece of code that is similar to the actual code and gives the same error.
import Data.Vector.Unboxed as D
xs = [0,1,2,3,4,5,6,7,8,9,10,11]
rows = 3
cols = 4
sb = D.fromList xs
takeRows::Int -> Int -> Vector Int -> Vector (Vector Int)
takeRows rows cols x0 = D.map (\x -> D.slice x (fromIntegral cols) x0) starts
where
starts = D.enumFromStepN 0 cols rows
-- takeRowsList::Int -> Int -> Vector Int -> [Vector Int]
-- takeRowsList rows cols x0 = Prelude.map (\x -> D.slice x (fromIntegral cols) x0) starts
-- where
-- starts = D.toList . D.enumFromStepN 0 cols $ rows
the error is
No instance for (Unbox (Vector Int))
arising from a use of `D.map'
Possible fix: add an instance declaration for (Unbox (Vector Int))
In the expression:
D.map (\ x -> slice x (fromIntegral cols) x0) starts
In an equation for `takeRows':
takeRows rows cols x0
= D.map (\ x -> slice x (fromIntegral cols) x0) starts
where
starts = enumFromStepN 0 cols rows
I have written a similar function takeRowsList, which makes the outer Vector as a List and this doesn't suffer from the same problem. I've also included it above but commented it out, to demonstrate my problem.
I understand that some functions need type definitions, when, I use them with Unboxed Vectors. But in this case I am stumped as to where to put a type definition. I've tried pretty much type defining everything and I keep getting the above error.
Thanks in advance for your help.
Unboxed vectors need to know the size of their elements, and that size must be constant. Vectors can have different sizes, so they can't be elements of unboxed vectors. They could be elements of boxed vectors, though, so if lists aren't good for what you do, you can make it a boxed vector (import qualified Data.Vector as B
and qualify the relevant functions with B instead of D).
You cannot have an unboxed vector contain another vector. Only certain primitive datatypes can be unboxed, namely the ones for which Unbox
instances are defined. Vectors are not primitive datatypes.
What you can do is have your function return a normal (boxed) vector of unboxed vectors.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With