Haskell export current module with additional imported module

Question

Is it possible to write a module in Haskell, which re-exports a module in addition to exporting everything visible inside?

Lets consider following module:

module Test where import A  f x = x 

This module exports everything defined inside, so it exports f but does not re-export anything imported from A.

On the other hand, if I want to re-export the module A:

module Test (     module A,     f ) where import A  f x = x 

Is there a way to re-export A and export everything defined in Test without needing to explicitly write every function defined within Test?

Answer 1

There is a simple solution, just export the module from the module:

module Test     ( module Test     , module A     ) where  import Prelude() import A f x = x