Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

gson throws MalformedJsonException

Tags:

java

json

gson

I'm using gson to convert a json string to a Java-Object. The value of result2 is exactly the same as the value of result1. (Copied from debugger; Backslashs added)

The following exception is thrown while converting result1: com.google.gson.JsonSyntaxException: com.google.gson.stream.MalformedJsonException: Expected EOF at line 1 column 170

Converting result2 works fine.

The json string is valid according to jsonlint.com.

public static Userinfo getUserinfo()
{
    String result1 = http.POST("https://www.bitstamp.net/api/balance/",
                                postdata, true);
    String result2 = "{\"btc_reserved\": \"0\", \"fee\": \"0.5000\", \"btc_available\": \"0.10000000\", \"usd_reserved\": \"0\", \"btc_balance\": \"0.10000000\", \"usd_balance\": \"30.00\", \"usd_available\": \"30.00\"}";
    Gson gson = new Gson();
    Userinfo userinfo1 = gson.fromJson(result1, Userinfo.class); //throws Exception
    Userinfo userinfo2 = gson.fromJson(result2, Userinfo.class); //works fine

    return userinfo1;
}
private class Userinfo {

    public Userinfo(){
    }

    public float usd_balance;
    public float btc_balance ;
    public float usd_reserved;
    public float btc_reserved;
    public float usd_available;
    public float btc_available;
    public float fee;
    public float last_update;
}
like image 859
Non Avatar asked Jul 14 '12 13:07

Non


People also ask

What is malformed JSON exception?

public final class MalformedJsonException extends IOException. Thrown when a reader encounters malformed JSON. Some syntax errors can be ignored by calling JsonReader. setLenient(boolean) . See Also: Serialized Form.

What is setLenient in GSON?

setLenient. public GsonBuilder setLenient() By default, Gson is strict and only accepts JSON as specified by RFC 4627. This option makes the parser liberal in what it accepts.


2 Answers

I suspect that result1 has some characters at the end of it that you can't see in the debugger that follow the closing } character. What's the length of result1 versus result2? I'll note that result2 as you've quoted it has 169 characters.

GSON throws that particular error when there's extra characters after the end of the object that aren't whitespace, and it defines whitespace very narrowly (as the JSON spec does) - only \t, \n, \r, and space count as whitespace. In particular, note that trailing NUL (\0) characters do not count as whitespace and will cause this error.

If you can't easily figure out what's causing the extra characters at the end and eliminate them, another option is to tell GSON to parse in lenient mode:

Gson gson = new Gson();
JsonReader reader = new JsonReader(new StringReader(result1));
reader.setLenient(true);
Userinfo userinfo1 = gson.fromJson(reader, Userinfo.class);
like image 51
Daniel Martin Avatar answered Oct 16 '22 22:10

Daniel Martin


From my recent experience, JsonReader#setLenient basically makes the parser very tolerant, even to allow malformed JSON data.

But for certain data retrieved from your trusted RESTful API(s), this error might be caused by trailing white spaces. In such cases, simply trim the data would avoid the error:

String trimmed = result1.trim();

Then gson.fromJson(trimmed, T) might work. Surely this only covers a special case, so YMMV.

like image 20
ryenus Avatar answered Oct 16 '22 20:10

ryenus