Greet a user differently on the time of day - Bash Script

Question

I need to greet a user (using “Good morning”, “Good afternoon”, or “Good evening”) depending on the time of day.

I have already gained the users details ($userTitle $userName) however I am not sure how to greet someone differently depending on the time... any ideas?

Answer 1

h=`date +%H`

if [ $h -lt 12 ]; then
  echo Good morning
elif [ $h -lt 18 ]; then
  echo Good afternoon
else
  echo Good evening
fi

Answer 2

You could get the time like this:

TIME=$(date "+%H")

Then act on that value i.e

if [ $TIME -lt 12 ]; then
    echo "Good morning"
elif [ $TIME -lt 18 ]]; then
    echo "Good afternoon"
else
    echo "Good evening"
fi

Answer 3

Try doing this :

TIME=$(date "+%k")

if ((TIME < 12 )); then
    echo "Good morning"
elif ((TIME < 18 )); then
    echo "Good afternoon"
else
    echo "Good evening"
fi

NOTE

• with this syntax, no need to remember -ge and such. This is just like arithmetic
• ((...)) is an arithmetic command, which returns an exit status of 0 if the expression is nonzero, or 1 if the expression is zero. Also used as a synonym for let, if side effects (assignments) are needed. See http://mywiki.wooledge.org/ArithmeticExpression

Answer 4

hour=`date +%H`
if [ $hour -le 12 ]; then
    echo 'good morning'
elif [ $hour -ge 18 ]; then
    echo 'good evening'
else
    echo 'good afternoon'
fi

Answer 5

All other answers is correct except one detail. Command date +%H return number hours in format XX ( for example if time is 09:00:00, then it return "09" ). In bash numbers started with zero is octal numbers. So this nuance can cause errors.

For example:

if [ 09 > 10 ] 
then
    echo "it's something strange here"
fi

will print "it's something strange here".

Probably you chose time intervals, who are not cause such behavior. But for insurance you can write:

hours=date +"%H" | sed -e 's/^0//g'

Be carefull.