Looking at <code>></code> in Racket, the following makes sense: <pre class="prettyprint"><code>> (> 5 0) #t </code></pre> Why does the following evaluate to false? <pre class="prettyprint"><code>> (> 5 0 0) #f </code></pre>

Because <code>(> 5 0 0)</code> is the same as: <pre class="prettyprint"><code>(and (> 5 0) (> 0 0)) </code></pre> ...Which is <code>#f</code>. For comparison, evaluate <code>(>= 5 0 0)</code> and you'll see that it returns <code>#t</code>.

Pronounce <code>></code> as strictly decreasing and <code>>=</code> as non-increasing. Then it becomes easy to see that <code>(> 5 0 0)</code> is false.