Use a temp table to insert the range of values, then select the min/max of the temp table from within a stored procedure or UDF. This is a basic construct, so feel free to revise as needed.
To find the minimum value of a column, use the MIN() aggregate function; it takes as its argument the name of the column for which you want to find the minimum value. If you have not specified any other columns in the SELECT clause, the minimum will be calculated for all records in the table.
with ID/Col as the primary key (and possibly Col as an extra key, depending on your needs). Then your query becomes a simple select min(val) from tbl and you can still treat the individual 'old columns' separately by using where col = 2 in your other queries.
SQL Server 2012 and 2014 supports IIF(cont,true,false) function. Thus for minimal selection you can use it like
SELECT IIF(first>second, second, first) the_minimal FROM table
While IIF is just a shorthand for writing CASE...WHEN...ELSE
, it's easier to write.
The solutions using CASE, IIF, and UDF are adequate, but impractical when extending the problem to the general case using more than 2 comparison values. The generalized solution in SQL Server 2008+ utilizes a strange application of the VALUES clause:
SELECT
PaidForPast=(SELECT MIN(x) FROM (VALUES (PaidThisMonth),(OwedPast)) AS value(x))
Credit due to this website: http://sqlblog.com/blogs/jamie_thomson/archive/2012/01/20/use-values-clause-to-get-the-maximum-value-from-some-columns-sql-server-t-sql.aspx
Use Case:
Select Case When @PaidThisMonth < @OwedPast
Then @PaidThisMonth Else @OwedPast End PaidForPast
As Inline table valued UDF
CREATE FUNCTION Minimum
(@Param1 Integer, @Param2 Integer)
Returns Table As
Return(Select Case When @Param1 < @Param2
Then @Param1 Else @Param2 End MinValue)
Usage:
Select MinValue as PaidforPast
From dbo.Minimum(@PaidThisMonth, @OwedPast)
ADDENDUM: This is probably best for when addressing only two possible values, if there are more than two, consider Craig's answer using Values clause.
I just had a situation where I had to find the max of 4 complex selects within an update. With this approach you can have as many as you like!
You can also replace the numbers with aditional selects
select max(x)
from (
select 1 as 'x' union
select 4 as 'x' union
select 3 as 'x' union
select 2 as 'x'
) a
More complex usage
@answer = select Max(x)
from (
select @NumberA as 'x' union
select @NumberB as 'x' union
select @NumberC as 'x' union
select (
Select Max(score) from TopScores
) as 'x'
) a
I'm sure a UDF has better performance.
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