Get type of the parameter, templates, C++

Question

There is the following simplified data structure:

Object1.h

template <class T>
class Object1
{
  private:
     T a1;
     T a2;
  public:
     T getA1() {return a1;}
};

Object2.h

template <class T>
class Object2: public Object1 <T>
{
   private:
      T b1;
      T b2;
  public:
     T getB1() {return b1;}
}

Is there any way how to get type T of an object in the folowing function:

Functions.h

template <class Object>
void (Object *o1, Object *o2)
{
   T = o1.getA1();  //Is it possible to get T from object o1?
   ...
}

or we must give an additional information about data types of both objects:

template <class T, class Object>
void (Object *o1, Object *o2)
{
   T = o1.getA1();
   ...
}

Answer 1

Add a typedef :

template <class T>
class Object1
{
  private:
     T a1;
     T a2;
  public:
     T getA1() {return a1;}
     typedef T type;
};

template <class Object>
void foo(Object *o1, Object *o2)
{
   typename Object::type x = o1.getA1();
   ...
}

Answer 2

You can use this:

template <template<class> class Object, class T>
void func1(Object<T> &o1, Object<T> &o2)
{
   T x = o1.getA1();
}

Working example at http://www.ideone.com/t8KON .

Btw. if you use pointers as parameters, you have to use -> operator to call methods.