If I have a list like this
((0 1 2) (3 4 5) (6 7 8) (0 3 6) (1 3 7) (2 4 8) (0 4 8) (2 4 6))
And I want to find the index of (0 3 6)
, is there a built-in function to do this? POSITION
doesn't seem to work when the search item is itself a list.
See hyperspec. POSITION can take a :test
argument:
(position '(0 3 6) '((0 1 2) (3 4 5) (6 7 8) (0 3 6) (1 3 7) (2 4 8) (0 4 8) (2 4 6)) :test #'equal)) 3
The default test for POSITION (and other sequence operations) is EQL, by the way.
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