Get hard disk size in Python

Question

I am trying to get the hard drive size and free space using Python (I am using Python 2.7 with macOS).

I am trying with os.statvfs('/'), especially with the following code. Is it correct what I am doing? Which definition of the variable giga shall I use?

import os  def get_machine_storage():     result=os.statvfs('/')     block_size=result.f_frsize     total_blocks=result.f_blocks     free_blocks=result.f_bfree     # giga=1024*1024*1024     giga=1000*1000*1000     total_size=total_blocks*block_size/giga     free_size=free_blocks*block_size/giga     print('total_size = %s' % total_size)     print('free_size = %s' % free_size)  get_machine_storage() 

EDIT: statvfs is deprecated in Python 3, do you know any alternative?

Answer 1

For Python 2 till Python 3.3

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Notice: As a few people mentioned in the comment section, this solution will work for Python 3.3 and above. For Python 2.7 it is best to use the psutil library, which has a disk_usage function, containing information about total, used and free disk space:

import psutil  hdd = psutil.disk_usage('/')  print ("Total: %d GiB" % hdd.total / (2**30)) print ("Used: %d GiB" % hdd.used / (2**30)) print ("Free: %d GiB" % hdd.free / (2**30)) 

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Python 3.3 and above:

For Python 3.3 and above, you can use the shutil module, which has a disk_usage function, returning a named tuple with the amounts of total, used and free space in your hard drive.

You can call the function as below and get all information about your disk's space:

import shutil  total, used, free = shutil.disk_usage("/")  print("Total: %d GiB" % (total // (2**30))) print("Used: %d GiB" % (used // (2**30))) print("Free: %d GiB" % (free // (2**30))) 

Output:

Total: 931 GiB Used: 29 GiB Free: 902 GiB