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Get Current date in epoch from Unix shell script

Tags:

shell

unix

epoch

People also ask

How do I get current epoch time in Unix?

Convert from human-readable date to epochlong epoch = new java.text.SimpleDateFormat("MM/dd/yyyy HH:mm:ss").parse("01/01/1970 01:00:00").getTime() / 1000; Timestamp in seconds, remove '/1000' for milliseconds. date +%s -d"Jan 1, 1980 00:00:01" Replace '-d' with '-ud' to input in GMT/UTC time.

How do I get the current date in Unix shell script?

Sample shell script to display the current date and time #!/bin/bash now="$(date)" printf "Current date and time %s\n" "$now" now="$(date +'%d/%m/%Y')" printf "Current date in dd/mm/yyyy format %s\n" "$now" echo "Starting backup at $now, please wait..." # command to backup scripts goes here # ...

How do I find my epoch date?

Multiply the two dates' absolute difference by 86400 to get the Epoch Time in seconds – using the example dates above, is 319080600.

How do I get current date in bash?

To get current date and time in Bash script, use date command. date command returns current date and time with the current timezone set in the system.


The Unix Date command will display in epoch time

the command is

date +"%s"

https://linux.die.net/man/1/date

Edit: Some people have observed you asked for days, so it's the result of that command divided by 86,400


Update: The answer previously posted here linked to a custom script that is no longer available, solely because the OP indicated that date +'%s' didn't work for him. Please see UberAlex' answer and cadrian's answer for proper solutions. In short:

  1. For the number of seconds since the Unix epoch use date(1) as follows:

    date +'%s'
    
  2. For the number of days since the Unix epoch divide the result by the number of seconds in a day (mind the double parentheses!):

    echo $(($(date +%s) / 60 / 60 / 24))
    

echo $(($(date +%s) / 60 / 60 / 24))

echo `date +%s`/86400 | bc