Generating hex numbers of a certain range

Question

I need a simple way to generate a .txt file with a list of semi-colon delimited hex numbers between (inclusive) a certain start and finish value.

For example:

If I enter 0 and FFF it would pad the output with zeroes to the largest number:

000;001;002;003;004;005;006;007;008;009;00A;00B;00C;00D;00E;00F;010;011;....FFF;

If I enter FFF and 1200 it would output those values...etc:

0FFF;1000;1001;1002;.....1200;

Any suggestions? I'm not a programmer so the best, simplest way to do this is way beyond me.

Answer 1

I just like to use simple for loops. You can add as many nested loops as you like for each digit:

for i in {0..9} {a..f}; do for x in {0..9} {a..f}; do for y in {0..9} {a..f}; do printf "$i$x$y;"; done; done; done

Output should look like this:

000;001;002;003;004;005;006;007;008;009;00a;00b;00c;00d;00e;00f;010;011;012;013;014;015;016;017;018...ff8;ff9;ffa;ffb;ffc;ffd;ffe;fff;

That was a one-liner, but let me give it some structure:

for i in {0..9} {a..f}
do
   for x in {0..9} {a..f}
   do
      for y in {0..9} {a..f}
      do
         printf "$i$x$y;"
      done
   done
done